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4-1.Newton's Laws of Motion
easy
A body, under the action of a force $\vec F = 6\hat i - 8\hat j + 10\hat k$, acquires an acceleration of $1\, m/s^2$ The mass of this body must be
A$15\,kg$
B$20\,kg$
C$10\sqrt 2 \,kg$
D$2\sqrt {10} \,kg$
(AIPMT-2009) (AIPMT-1996)
Solution
$\begin{array}{l}
\,\,\,\,\,\,\vec F\, = 6\hat i – 8\hat j + 10\hat k\\
\left| {\vec F} \right| = \sqrt {36 + 64 + 100} = \sqrt {200} N = 10\sqrt 2 \,N.\\
Acceleration,\,a = 1\,m/{s^{ – 2}}\\
\therefore \,\,Mass,\,M\, = \frac{{10\sqrt 2 }}{1} = 10\sqrt 2 kg.
\end{array}$
\,\,\,\,\,\,\vec F\, = 6\hat i – 8\hat j + 10\hat k\\
\left| {\vec F} \right| = \sqrt {36 + 64 + 100} = \sqrt {200} N = 10\sqrt 2 \,N.\\
Acceleration,\,a = 1\,m/{s^{ – 2}}\\
\therefore \,\,Mass,\,M\, = \frac{{10\sqrt 2 }}{1} = 10\sqrt 2 kg.
\end{array}$
Standard 11
Physics
